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### Course: Algebra 2 > Unit 5

Lesson 4: Putting it all together# Graphs of polynomials

Analyze polynomials in order to sketch their graph.

#### What you should be familiar with before taking this lesson

The $f$ describes the behavior of its graph at the "ends" of the $x$ -axis. Algebraically, end behavior is determined by the following two questions:

**end behavior**of a function- As
, what does$x\to +\mathrm{\infty}$ approach?$f(x)$ - As
, what does$x\to -\mathrm{\infty}$ approach?$f(x)$

If this is new to you, we recommend that you check out our end behavior of polynomials article.

The zeros of a function $f$ correspond to the $x$ -intercepts of its graph. If $f$ has a zero of $x$ -axis at that $x$ value. If $f$ has a zero of $x$ -axis at that point.

*odd*multiplicity, its graph will*cross*the*even*multiplicity, its graph will*touch*theIf this is new to you, we recommend that you check out our zeros of polynomials article.

#### What you will learn in this lesson

In this lesson, we will use the above features in order to analyze and sketch graphs of polynomials. We will then use the sketch to find the polynomial's positive and negative intervals.

## Analyzing polynomial functions

We will now analyze several features of the graph of the polynomial $f(x)=(3x-2)(x+2{)}^{2}$ .

### Finding the $y$ -intercept

To find the $y$ -intercept of the graph of $f$ , we can find $f(0)$ .

The $y$ -intercept of the graph of $y=f(x)$ is $(0,-8)$ .

### Finding the $x$ -intercepts

To find the $x$ -intercepts, we can solve the equation $f(x)=0$ .

$\begin{array}{rl}f(x)& =(3x-2)(x+2{)}^{2}\\ \\ {0}& =(3x-2)(x+2{)}^{2}\\ \end{array}$ $\begin{array}{rlr}& \swarrow & \searrow \\ \\ 3x-2& =0& \text{or}{\textstyle \phantom{\rule{1em}{0ex}}}x+2& =0& {\text{Zero product property}}\\ \\ x& ={\displaystyle \frac{2}{3}}& \text{or}{\textstyle \phantom{\rule{2em}{0ex}}}x& =-2\end{array}$

The $x$ -intercepts of the graph of $y=f(x)$ are $({\displaystyle \frac{2}{3}},0)$ and $(-2,0)$ .

Our work also shows that $\frac{2}{3}$ is a zero of multiplicity $1$ and $-2$ is a zero of multiplicity $2$ . This means that the graph will cross the $x$ -axis at $({\displaystyle \frac{2}{3}},0)$ and touch the $x$ -axis at $(-2,0)$ .

### Finding the end behavior

To find the end behavior of a function, we can examine the leading term when the function is written in standard form.

Let's write the equation in standard form.

The leading term of the polynomial is ${3{x}^{3}}$ , and so the end behavior of function $f$ will be the same as the end behavior of $3{x}^{3}$ .

Since the degree is odd and the leading coefficient is positive, the end behavior will be: as $x\to +\mathrm{\infty}$ , $f(x)\to +\mathrm{\infty}$ and as $x\to -\mathrm{\infty}$ , $f(x)\to -\mathrm{\infty}$ .

### Sketching a graph

We can use what we've found above to sketch a graph of $y=f(x)$ .

Let's start with end behavior:

- As
,$x\to +\mathrm{\infty}$ .$f(x)\to +\mathrm{\infty}$ - As
,$x\to -\mathrm{\infty}$ .$f(x)\to -\mathrm{\infty}$

This means that in the "ends," the graph will look like the graph of $y={x}^{3}$ .

Now we can add what we know about the $x$ -intercepts:

- The graph touches the
-axis at$x$ , since$(-2,0)$ is a zero of even multiplicity.$-2$ - The graph crosses the
-axis at$x$ , since$({\displaystyle \frac{2}{3}},0)$ is a zero of odd multiplicity.$\frac{2}{3}$

Finally, let's finish this process by plotting the $y$ -intercept $(0,-8)$ and filling in the gaps with a smooth, continuous curve.

While we don't know exactly where the turning points are, we still have a good idea of the overall shape of the function's graph!

### Positive and negative intervals

Now that we have a sketch of $f$ 's graph, it is easy to determine the intervals for which $f$ is positive, and those for which it is negative.

We see that $f$ is positive when $x>{\displaystyle \frac{2}{3}}$ and negative when $x<-2$ or $-2<x<{\displaystyle \frac{2}{3}}$ .

## Check your understanding

**1)**You will now work towards a sketch of

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